Maximum rate of climb

A balloon has a maximum rate of climb, which is reached when the inner preasure(temperatur) is equal to the aerodynamic preasure (~v2)on the outside of the parachute. Does anybody know about an experimental approach to this solution?

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weird units!

To use the envelope more than one time, the maximum climbing depends mainly on the outside temperature and the maximum temperature you can heat the air inside the envelope (about 100 to 110°C). This results in about 5 meters/second. (= 984 ft/min = 197 '/sec = 9.72 kt = 11.2 mph)

Holger Galuschka PPL-D, Germany

The theoretical max rate of climb depends, among other factors, on the inner preasur of the balloon. This means of the temperature. This means on the specific load of the balloon. For a 105'(3000m3) normaly loaded, vmax ~8,5m/sec (approx 1700ft/min), a lightly loaded balloon rather 5,5 m/sec (1100 ft/min. If somebody is interested in the theoretical approach, I will deliver it. I'm interested if somebody know about an experimental confirmation of this theory.

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